A body is rpojected vertically upwards with a velocity of `10m//s`. If reaches the maximum height (h) in time (t). In time ` t//2` the height covered is (g= 10 m//s^@)`

A body is projected vertically upwards with a velocity of 10m//s . It reaches the maximum vertical height in time t. What will be the height covered in time t/2 ?

A ball is projected vertically upward with a speed of 50 m/s. Find the time to reach the maximum height,

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body.(g=9.8 m/s^2)

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body. (g=9.8m//s^(2))

A ball is thrown vertically upwards with a velocity of 4.9m/s Find (i) the maximum height reached by the ball (ii) time taken to reach the maximum height

A ball is projected vertically upward with a speed of 50 m//s. Find (a) the maximum height, (b) the time to reach the maximum height, (c) the speed at half the maximum height. Take g=10 ms^2.

A ball is projected vertically upward with a speed of 50 m//s. Find (a) the maximum height, (b) the time to reach the maximum height, (c) the speed at half the maximum height. Take g=10 ms^2.

A ball is projected vertically up with a speed of 50 m/s. Find the maximum height , the time to reach the maximum height, and the speed at the maximum height (g=10 m//s^(2)) (AS_(1))