The solution of differential equation ` t = 1 + (ty)(dy)/(dt) + (ty)^2/(2!) ((dy)/(dt))^(2)+ . . . . oo ` is

Solution of differential equation (dt)/(dx)=(xlogx)/(t) is

The solution of differential equation (dt)/(dx) = (t[d/dx{g(x)}]-t^(2))/(g(x) ) is

Solve (dy)/(dt) = t^(2).

solve the differential equation (1+t^2)dx/dt=2t

If y(t) is the solution of the differential equation (t+1)(dy)/(dt)-ty=1 and y(0)=-1 , then the value of y at t=1 is -

Solve (dy)/(dt)=(1+t)^2