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" 26."(1)/(x-2)+(2)/(x-1)=(6)/(x),x!=0...

" 26."(1)/(x-2)+(2)/(x-1)=(6)/(x),x!=0

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Solve for x: (1)/(x-2)+(2)/(x-1)=(6)/(x) ,x ne 0,1,2

Solve for x: (6)/(x)-(2)/(x-1)=(1)/(x-2);x!=0,1,2

(x+1)(x-3)(x+2)(x-4)+6=0

solve by factorisation: 3x^(2)-2sqrt(6)x+2=0 and (1)/(x-1)-(1)/(x+5)=(6)/(7)

((x-2))/((x+2))+6((x-2)/(x-6))=1,x!=-2,6

Solve (x^(2)+(1)/(x^(2)))-5(x+(1)/(x))+6=0," when "x ne0

1/((x-2)(x-4))+1/((x-4)(x-6))+1/((x-6)(x-8))+1/3=0

Long-answer type questions (L.A.) (x-2)/(x+2)+6((x-2)/(x-6))=1,(xne-2,6)

If A = [(2,1),(0,x)] and A^(-1) = [((1)/(2),(1)/(6)),(0,(1)/(x))] , then the value of x is equal to