5a-[a^(2)-{2a(1-a+4a^(2))-3a(a^(2)-5a-3)

(5a^(3)-4a^(2)+3a+18)/(a^(2)-2a+3)

Simplify : a^(2) - 2a + {5a^(2) - 3a - 4a^(2)}

Add the following -2a+5a^2-a^3+2, -5a^2 -2a^3 +4, a-a^2 +3a^3, -2a-3a^2-4, 6-3a+2a^2-2a^3

The sum of the infinite series,1^(2)-(2^(2))/(5)+(3^(2))/(5^(2))-(4^(2))/(5^(3))+(5^(2))/(5^(4))......is

(1+(a^(2)x^(2))/(2!)+(a^(4)x^(4))/(4!)+....)^(2)-(ax+(a^(3)x^(3))/(3!)+(a^(5)x^(5))/(5!)+....)^(2)=

Take away :(5a^(2))/(2)+(3a^(3))/(2)+(a)/(3)-(6)/(5) om (1)/(3)a^(3)-(3)/(4)a^(2)-(5)/(2)

If a^(2)+b^(2)+c^(2)=1 where, a,b, cin R , then the maximum value of (4a-3b)^(2) + (5b-4c)^(2)+(3c-5a)^(2) is

If a^(2)+b^(2)+c^(2)=1 where, a,b, cin R , then the maximum value of (4a-3b)^(2) + (5b-4c)^(2)+(3c-5a)^(2) is

If a^(2)+b^(2)+c^(2)=1 where, a,b, cin R , then the maximum value of (4a-3b)^(2) + (5b-4c)^(2)+(3c-5a)^(2) is