If KE of the particle of mass m performing UCM in a circle of radius r is E. Find the acceleration of the particle

Centripetal acceleration of a particle of mass m moving in a circle of radius r is 4//r^(2) . What is the angular momentum of the particle ?

Centripetal acceleration of a particle of mass m moving in a circle of radius r is 4//r^(2) . What is the angular momentum of the particle ?

A particle of mass M is revolving along a circule of radius R and nother particle of mass m is recolving in a circle of radius r . If time periods of both particles are same, then the ratio of their angular velocities is

A particle of mass M is revolving along a circule of radius R and nother particle of mass m is recolving in a circle of radius r . If time periods of both particles are same, then the ratio of their angular velocities is

A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is (4)/(r^(2)) . What will be the momentum of the particle ?

A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is (4)/(r^(2)) . What will be the momentum of the particle ?

A particle performing a U.C.M. has a

A particle performing a U.C.M. has a

A particle of mass m impves along a horzontal circle of radius R such that normal acceleration of particle varies with time as a_(n)=kt^(2). where k is a constant. Total force on particle at time t s is