`cos^2theta=3/4,theta in [0,pi]`

Solve the following equations cos^(2) theta = (3)/(4), theta in [0, pi]

The sum of all the solution is of the equation cos theta cos ((pi)/3+theta)cos ((pi)/3-theta)=1/4, theta in [0,6pi ]

Solve for theta,theta in[0,pi],cos theta cos2 theta cos3 theta=(1)/(4)

The solution of costheta.cos2theta.cos3theta=1/4,0 lt theta lt pi/4 is:

If (sin^(3)theta-cos^(3)theta)/(sin theta-cos theta)-(cos theta)/(sqrt(1+cot^(2)theta))-2 tan theta cot theta=-1 (AA theta in[0, 2pi], then

The value of theta lying between 0 and pi/2 and satisfying the equation |[1+sin^2theta,cos^2theta,4sin4theta] , [sin^2theta,1+cos^2theta,4sin4theta] , [sin^2theta,cos^2theta,1+4sin4theta]|=0 (A) (7pi)/24 or (11pi)/24 (B) (5pi)/24 (C) pi/24 (D) none

The value of theta lying between 0 and pi/2 and satisfying the equation |(1+cos^2theta, sin^2theta, 4sin4theta),(cos^2theta, 1+sin^2theta, 4sin4theta),(cos^2theta, sin^2theta, 1+4sin4theta)|=0 is (are) (A) (7pi)/24 (B) (3pi)/8 (C) (11pi)/24 (D) (7pi)/12