If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force ` (-1//r^(2))` , the total energy is

IF a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-(K)/(r^(2))) , then its total energy is

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to - (K//r^(2)) , where K is constant. What is the total energy of the particle ?

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to - (K//r^(2)) . Where K is constant. What is the total energy of the particle?