If for distribution of 18 observations `sum(x_i-5)=3a n dsum(x_i-5)^2=43 ,` find the mean and standard deviation.

If for distribution of 18 observations sum(x_(i)-5)=3 and sum(x_(i)-5)^(2)=43, find the mean and standard deviation.

If for distribution sum(x-7)=3 , sum(x-7)^(2)=57 and total number of item is 20 . Find the mean and standard deviation.

If for a distribution sum(x-5) = 3, sum(x - 5)^2 = 43 and the total number of item is 18, find the mean and standard deviation.

If the mean and standard deviation of 75 observations is 40 and 8 respectively, find the new mean and standard deviation if (i) each observation is multiplied by 5. (ii) 7 is added to each observation.

If for a distribution, sum (x-5)=3, sum (x-5)^(2)=43 and total number of observations is 18, find the mean and standard deviation.

If, s is the standard deviation of the observations x_(1),x_(2),x_(3),x_(4) and x_(5) then the standard deviation of the observations kx_(1),kx_(2),kx_(3),kx_(4) and kx_(5) is

If, s is the standard deviation of the observations x_(1),x_(2),x_(3),x_(4) and x_(5) then the standard deviation of the observations kx_(1),kx_(2),kx_(3),kx_(4) and kx_(5) is

If for a distribution sum(x-5)=3,sum(x-5)^(2)=43 and the total number of terms is 18 then mean and variance are

Let x_(1),x_(2),...,x, are n observations such that sum_(i=1)^(t)x_(1)=10 and sum_(i=1)^(n)x_(i)^(2)=260 and standard deviation is 5 then n is equal to