If the above radial probaility curve indicates '2s' orbital, the distance between the peak points X& Y
is

The distance between the points (x,-y) and (-x,y) is

Draw the radial probability curves of s, p and d orbitals.

Find the shortest distance between the curve x^2+y^2=4 and the point (6,8)

In the radial probability distribution curve for the 2s orbital of the hydrogen atom, the minor maximum, the node and the major maximum occur at the following distances from the nucleus respectively

The shortest distance between y-x=1 and curve x=y^(2) is :

The shortest distance between y-x=1 and curve x=y^(2) is :

Show that the curve such that the distance between the origin and the tangent at an arbitrary point is equal to the distance between the origin and the normal at the same point sqrt(x^2+y^2) =ce^(+-tan^(-1y/x))