If G is the centroid of `Delta ABC and G' ` is the centroid of `Delta A' B' C' " then " vec(A A)' + vec(B B)' + vec(C C)' = `

If G is the centroid of Delta ABC, G' is the centroid of Delta A' B' C' then vec(A)A' + vec(B)B' + vec(C)C' =

If G is the centroid of Delta ABC then vec(G)A + vec(G)B + vec(G)C =

If A, B, C are vertices of a triangle whose position vectors are vec a, vec b and vec c respectively and G is the centroid of Delta ABC, " then " vec(GA) + vec(GB) + vec(GC), is

If the centroids of DeltaABC and Delta A'B'C' are respectively G and G' then vec(A A')+vec(BB')+vec(C C') ……………….. .

If D is the midpoint of the side BC of Delta ABC then vec(A)B + vec(A)C =

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

G is the centroid of a triangle ABC, show that : vec(GA)+vec(GB)+vec(GC)=vec0 .

If G is the centroid of a triangle ABC, prove that vec(GA)+vec(GB)+vec(GC) = 0