[SiF_(6)]^(2-)" is known whereas "[SiCl_(6)]^(2-)" not.Give possible reasons."

[SiF_(6)]^(2-) is known where as [SiCl_(6)]^(2-) not. Reason is

[SiF_(6)]^(2-) is known where as [SiCl_(6)]^(2-) not. Reason is

a. Select the member s of grop 14 that (i) forms the most acidic diozide (ii) is commonly found in +2 oxidation state and (iii) used as se,ocpmdictpr . (Solved NCEGT Pronlem 11.5 ) b. |SiF_5^(2-) is known, whereas |SiCl_5|^(2-) not. Glve possible preasons . (Solved NCEGT Pronlem 11.6 ) c . Diamond is covalent , yet covelnt , yet it has high melting point . Why ? (Solved NCEGT Pronlem 11.7 ) .

[SiF_(6)]^(2-) is known whereas [SiC_(6)]^(2-) not. The main reason is/are I Six large chloride ions cannot be accommodated around Si^(4+) due to limitation of its size. II. Interaction between lone pair of chloride ion and Si^(4+) is not very strong. Choose the correct option.

[SiF_6]^(2-) is known but [SiCI_6]^(2-) is not. Give reasons.

SiF_6^(2-) is known while SiCl_6^(-2) is not - explain.

[SiF_6]^(2-) is known to exist whereas [CF_6]^(2-) does not exist. Explain.