If `bara=i+j+k,bara.barb=1` and `baraxxbarb=j-k`, then : `barb`=

If bara=bari+barj+bark,bara.barb=1,baraxxbarb=2bari+barj-3bark then 3barb=

If abs(bara)=2,abs(barb)=3 and bara.barb=0 , then : baraxx{baraxx[baraxx(baraxxbarb)]}=

Let bara and barb be two non-collinear unit vectors. If baru=bara-(bara.barb)barb and barv=bara xx barb , then |barv|=

If bara=2i+3j-k,barb=-i+2j-4k and barc=i+j+k , then (baraxxbarb).(baraxxbarc)=

If abs(bara+barb) = abs(bara-barb), " then " bara.barb =

The vectors bara,barb and bara+barb are

The vectors bara,barb and bara+barb are

If abs(bara)=abs(barb)=1 and [[bara, barb ,baraxxbarb]]=1/4 , then mangle(bara,barb) =

Let bara and barb be two non coplanar unit vectors IF baru=bara-(bara.barb)barb and barv=bara times barb then |barv| is

If bara is collinear with barb =3i + 6j + 6k and bara.barb=27 , then bara =