cot4x=0

General solution of cot4x=-1 is

(i) sec3x=-2 (ii) cot4x=-1 (iii) "cosec "3x=(-2)/(sqrt(3))

tan^(-1)(cot4x)

Let f: (-(pi)/(4), (pi)/(4)) rarr R be defined as f(x)= {((1+|sin x|)^((3a)/(|sin x|))",",-(pi)/(4) lt x lt 0),(b",",x=0),(e^(cot 4x//cot 2x)",",0 lt x lt (pi)/(4)):} If f is continuous at x = 0, then the value of 6a+b^(2) is equal to

Let f be defined as f(x)= {((1+|sin x|)^((3a)/(|sin x|))",",-(pi)/(4) lt x lt 0),(b",",x=0),(e^(cot 4x//cot 2x)",",0 lt x lt (pi)/(4)):} If f is continuous at x = 0, then the value of 6a+b^(2) is equal to

lim_(x rarr0)(x cot4x)/((cot^(2)2x)(sin^(2)x)) is equal to (A) 1 (B) 2(C)4(D)6

Domain of the function f(x)=sec2x+cot4x is

Prove that cot4x(sin5x + sin3x) = 2cos4x cosx

lim_(x to 0)(x cot(4x))/(sin^(2) x cot^(2)(2x)) is equal to

Period of 118.(sin2x)-143(cot4x) is