200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be `2.57 xx 10^(-3)` bar. The molar mass of protein will be `(R = 0.083 L bar mol^(-1)K^(-1))`

200 ml of an aqueous solution of a protein contains 1.26 g of protein. At 300 K, the osmotic pressure of this solution is found to be 2.52xx 10^(-3) bar.The molar mass of protein will be (R=0.083 L bar mol ^(-1) K^(-1))

1000 cm^3 of an aqueous solution of a protein contain 1.26gm of the protein. The osmotic pressure of such a solution at 300 K is found to be 2.57xx10^(-3) bar. Calculated molar mass of the protein (R = 0.083L bar mol^(-1)K^(-1) )

200 cm^(3) of an aqueous solution of a protein contains 1.26 g of protein. The osmotic pressure of such a solution at 300 K is found to be 2.57 xx 10^(-3) bar. Calculate the molar mass of the protein. (R = 0.083 L bar "mol"^(-1)K^(-1) )