Decomposition of phosphine `(PH_(3))` at `120^(@)` C proceeds according to the equation
`4PH_(3)(g) to P_(4)(g) + 6H_(2)(g)`
It was found that the reactioin follows the rate equation, Rate = `k[PH_(3)]`
The half life period of `PH_(3)` is 37.9 s at `120^(@)`C.
i) How much time will be required for `3//4` of `PH_(3)` to decompose? ltrbgt ii) What function of the original amount of `PH_(3)` will remain undecomposed after 1 minute?

(a) Explain the following terms : (i) Rate of a reaction (ii) Activation energy of a reaction (b) The decompositon of phosphine , PH3, proceeds according to the following equation : 4 PH_(3) (g) to P_(4)(g) + 6 H_(2) (g) It is found that the reaction follows the following rate equation : Rate = k [ PH_(3)] . The half-life of PH_(3)" is "37.9" s at "120^(@)C . (i) How much time is required for 3//4^("th") "of " PH_(3) to decompose ? (ii) What fraction of the original sample of PH_(3) remains behind after 1 minute ?

The decomposition of phosphine, PH_3 , proceeds according to the following equation : 4PH_3 (g) rarr P_4 (g) + 6H_2 (g) It is found that the reaction follows the following rate equation : Rate = k[PH_3] . The half-life of PH_3 is 37.9 s at 120^@ C. How much time is required for 3/4th of PH_3 to decompose?

The decomposition of phosphine, PH_3 proceeds according to the following equation: 4PH_3 (g) to P_4 (g) + 6H_2 (g) It is found that the reaction follows the following rate equation: Rate =k[PH_3] The half-life of PH_3 is 37.9s at 120^@ C. How much time is required for 3/4th of PH_3 to decompose?