Each angle A, B,C of the triangle ABC is acute and sin (B+C-A)=1 , tan (C+A-B)=`sqrt(3)`, find A,B and C.

If A,B,C are the angles of an acute angled triangle and cos(B+C-A)=0, sin (C+A-B)=(sqrt(3))/2 , find the values of A,B , and C.

The angles A, B, C of triangle ABC are in A.P. and b:c = sqrt(3): sqrt(2) . Find A.

ABC is an acute angled triangle in which cosec (B+C-A) =1 and cot (C+A-B)=1/sqrt(3) , then tan C=

ABC is an acute angled triangle in which cosec (B+C-A) =1 and cot (C+A-B)=1/sqrt(3) , then sin A =

In an acute angled triangle ABC, if tan(A+B-C)=1 and ,sec(B+C-A)=2, find the value of A,B and C.

ABC is an acute angled triangle in which cosec (B+C-A) =1 and cot (C+A-B)=1/sqrt(3) , then sec B=

If A,B,C are positive acute angles and sin(B+C-A)=cos(C+A-B)=tan(A+B-C)=1 then A,B,C are

In a right angle triangle ABC, right angle is at B ,If tan A=sqrt(3) , then find the value of (i) sin A cos C+ cos A sin C "

In a right angle triangle ABC, right angle is at B ,If tan A=1/sqrt(3) , then find the value of (i) sin A cos C+ cos A sin C " "(ii) cos A cos C -sin A sin C