A suitcase is gently dropped on a conveyor belt moving at ` 3 m//s`. If the coefficient of friction between the belt and the suitcase is 0.5. Find the displacement of suitcase relative to conveyor belt before the slipping between the two is stopped `(g=10 m//s^(2))`

A suitcase is gently dropped on a conveyor belt moving at 3ms^(-1) If the coefficient of friction between the belt and suitcase is 0.5 how far will the suitcase move on the belt before coming to rest ?

A suitcase us gently dropped on a coneyor belt moving at 3 m// .If th coefficientt of friction between the belt and the surface is 0.5 ,how far will the suitcase move on the belt before coming to rest?

A package is at rest on a conveyor belt which is initially at rest. The belt is started and moves to the right for 1.3s with a coonstant acceleration of 2m//s^(2). The belt then moves with a constant deceleration and comes to stop after a total displacement of 2.2m. The coefficient of friction between the package and the belt are mu_(s) =0.35 and mu_(k) = 0.25 . The displacement of the package relative to the belt as the belt comes to stop is 317 xx 10^(-x) The value of x is (g = 10 m//s^(2))

A conveyor belt is moving at a constant speed of 2m//s . A box is gently dropped on it. The coefficient of friction between them is mu=0.5 . The distance that the box will move relative to belt before coming to rest on it taking g=10ms^(-2) is:

A conveyor belt is moving at a constant speed of 2m//s . A box is grenty dropped on it. Th ecoefficient of friction between them is mu=0.5 . The distance that the box will move relative to belt before coming to rest on it taking g=10ms^(-2) is: