A body of 2 kg falls from rest. What will be its kinetic energy during the fall at the end of 2 s ? (Assume `g = 10 m//s^(2)`)

A body of mass 2 kg is thrown vertically upwards with an initial velocity of 20 m/s. What will be its potential energy at the end of 2 s ? (Assume g = 10 m//s^(2) ).

A ball of mass 200 g falls from a height 5 metres. What is its kinetic energy when it just reaches the ground ? ( g = 9.8 m//s^(2) ).

A body of mass 10 kg falls from a height of 10 m. What will be its kinetic energy just before it touches the ground ? Prove that, this kinetic energy is equal to the potential stored at the initial position of the body. [g=980 cm *s^(-2) ]

A body of mass 1 kg is rotating in a verticle circle of radius 1 m .What will be the difference in its kinetic energy at the top and bottom of the circle ? (g=10m//s^(2))

A body of mass 10 kg at rest is subjected to a force of 16N. Find the kinetic energy at the end of 10 s

A body of mass 5 kg initially at rest is subjected to a force of 20 N. What is the kinetic energy acquired by the body at the end of 10 s?

A body of mass 2 kg moves with a velocity of 5 m/s. Find its kinetic energy.

A body of mass 10 kg is kept at a height of 5 m. It is allowed to fall and reach the ground. What is the kinetic energy possessed by the body just before hitting the ground? (Take g = 10m//s^(2) ).