A man runs at a speed of `4m//s` to overtake a standing bus. When he is `6m` beind the door at `t=0`, the bus mover forward and continuous with a constant acceleration of `1.2m//s^(2)`. The man reaches the door in time `t`. Then

A man runs at a speed of 4 ms to overtake a standing bus. When he is 6m behind the door (a ) the bus moves forward and continues moving with constant acceleration of 1.2 m/s^2 . The time after which the man is able to catch the bus is :

A person is running at his maximum speed of 4 m/s to catch a train .When he is 6m from the door of the compartment the train starts to leave the station at a constant accceleration of 1 m//s^(2) .Find how long it takes him to catch up the train

A person is running at his maximum speed of 4 m/s to catch a train. When he is 6 m from the door of the compartment the train starts to leave the station at a constant acceleration of 1 "m/s"^2 . Find how long it takes him to catch up the train

A person in running at his maximum speed of 4 m/s to catch a train when he is 6 m from the door of the compartment the train starts to leave the station at a constant accelration of 1 m//s^(2) find how long it takes him to catch up the train

A student is running at her top speed of 5.0 m s^(-1) , to catch a bus, which is stopped at the bus stop. When the student is still 40.0m from the bus, it starts to pull away, moving with a constant acceleration of 0.2 m s^(-2) . a For how much time and what distance does the student have to run at 5.0 m s^(-1) before she overtakes the bus? b. When she reached the bus, how fast was the bus travelling? c. Sketch an x-t graph for bothe the student and the bus. d. Teh equations uou used in part (a)to find the time have a second solution, corresponding to a later time for which the student and the bus are again at thesame place if they continue their specified motions. Explain the significance of this second solution. How fast is the bus travelling at this point? e. If the student s top speed is 3.5 m s^(-1), will she catch the bus? f. What is the minimum speed the student must have to just catch up with the bus?For what time and what distance dies she have to run in that case?

A student is running at her top speed of 5.0 m s^(-1) , to catch a bus, which is stopped at the bus stop. When the student is still 40.0m from the bus, it starts to pull away, moving with a constant acceleration of 0.2 m s^(-2) . a For how much time and what distance does the student have to run at 5.0 m s^(-1) before she overtakes the bus? b. When she reached the bus, how fast was the bus travelling? c. Sketch an x-t graph for bothe the student and the bus. d. Teh equations uou used in part (a)to find the time have a second solution, corresponding to a later time for which the student and the bus are again at thesame place if they continue their specified motions. Explain the significance of this second solution. How fast is the bus travelling at this point? e. If the student s top speed is 3.5 m s^(-1), will she catch the bus? f. What is the minimum speed the student must have to just catch up with the bus?For what time and what distance dies she have to run in that case?