The moment of inertia of a uniform rod about a perpendicular axis passing through one end is `I_(1)`. The same rod is bent into a ring and its moment of inertia about a diameter is `I_(2)`. Then `I_(1)//I_(2)` is

The M.I. of a uniform rod about a perpendicular axis passing through one of its ends is I_(1) . The same rod is bent into a ring and its moment of inertia about a diameter is I_(2) . Then (I_(1))/(I_(2)) is

The moment of inertia of a thin uniform rod rotating about the perpendicular axis passing through one end is 'I'. The same rod is bent into a ring and its moment of inertia about the diameter is I_1 . The ratio I/I_1 is

Moment of interia of a thin uniform rod rotating about the perpendicular axis passing through its center is I. If the same rod is bent into a ring and its moment of inertia about its diameter is

Moment of inertia of a thin uniform rod rotating about the perpendicular axis passing through its centre is I. If the same rod is bent into a ring and its moment of inertia about its diameter is I', then the ratio I//I' is,

If I_(1) is the moment of inertia of a uniform rod about an axis perpendicular to its length and passing through its one end. Now ring formed by bending the rod, if the moment of inertia about the diameter of ring I_(1) then (I_(1))/(I_(2)) = ……….

Moment of inertia of a straight wire about an axis perpendicular to the wire passing through one of its end is I. Now the same wire is bent into a ring of two turns , then the moment of inertia would be

The moment of inertia of a uniform ring about an axis passing through its centre and perpendicular to its plane is 100kgm^(2) . What is the moment of inertia of the ring about its diameter ?