A particle position as function of time is discribed as ` y (t) =5 cos (10 t + 15) in metres. What is the average velocity of the partilcle from ` t=0` ot ` t= 3 sec` ?

A particle position as function of time is described as y (t) =5 cos (10 t + 15) in meters. What is the average velocity of the particle from t=0 at t= 3 sec ?

A particle's position as a function of time is described as y (t) = 2t^(2) + 3t + 4 . What is the average velocity of the particle from t = 0 to t = 3 sec ?

The velocity of an object moving rectilinearly is given as a function of time by v=4t-3t^(2) where v is in m/s and t is in seconds. The average velocity if particle between t=0 to t=2 seconds is

The position-time relation of a moving particle is x = 2t -3t^(2) . What is the maximum positive velocity of the particle?

The position time relation of a moving particle is x = 2t - 3t^2 What is the maximum (+) ve velocity of the particle?

The position-time relation of a moving, particle is x = 2t - 3t^2 :- What is the maximum (+) ve velocity of the particle?

The position of a particle varies with function of time as y=(4sin t+3cos t)m . Then the maximum displacement of the particle from origin will be

The position of a particle is given by vec r= 3.0 t hat i - 2.0 t^2 hat j + 4.0 hat k m , wher (t) in seconds and the coefficients have the proper units for vec r to be in metres. what is the magnitude of the velocity of particle at t=2 sec ?