White phosphorus reacts with chlorine and the product hydrolyses in the presence of water. Calculate the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water.

Explanation

`underset(1 mol)(P_(4) + 6Cl_(2)) + 12H_(2)O to 4H_(3)PO_(3) + underset(12 "mol")(12HCl)`
`therefore 0.5` mol
`therefore` Moles of HCl obtained `=12 xx 0.5 = 6`
`therefore` Mass of HCl obtained = Moles x Mol. Mass
`=6 xx 36.5`
`=219.0` g