Home
Class 11
PHYSICS
At highest point velocity of projectile ...

At highest point velocity of projectile is …... (`theta` = angle of projection).

Text Solution

Verified by Experts

The correct Answer is:
`ucostheta`
Promotional Banner

Topper's Solved these Questions

  • OBJECTIVE QUESTIONS AS PER NEW PAPER STYLE

    KUMAR PRAKASHAN|Exercise CHAPTER - 4 (Are the following statements True or False ? )|10 Videos
  • OBJECTIVE QUESTIONS AS PER NEW PAPER STYLE

    KUMAR PRAKASHAN|Exercise CHAPTER - 4 (Match Type Questions)|4 Videos
  • OBJECTIVE QUESTIONS AS PER NEW PAPER STYLE

    KUMAR PRAKASHAN|Exercise CHAPTER - 3 (Match Type Questions)|4 Videos
  • MOTION IN A STRAIGHT LINE

    KUMAR PRAKASHAN|Exercise QUESTION PAPER|11 Videos
  • OSCILLATIONS

    KUMAR PRAKASHAN|Exercise QUESTION PAPER (SECTION - D)|1 Videos

Similar Questions

Explore conceptually related problems

At highest point acceleration of projectile is zero.

Maximum range of projectile depend on angle of projectile.

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

A body is projected at an angle of 45^(@) with horizontal with velocity of 40sqrt(2)m//s . Find out (i) Maximum height attained by body (ii) Time of flight (iii) Horizontal range (iv) Velocity at maximum height (v) The ratio of Kinetic energy to potential energy at highest point (vi) The part equation of projectile, assuming point of projection as origin and consider x and y are horizontal and vertical distance in meter (vii) The horizontal distance covered by body in 2 second (viii) The vertical distance covered by body in 2 second

A projectile fired with initial velocity u at some angle theta has a range R . If the initial velocity be doubled at the same angle of projection, then the range will be

Statement-I : Path of a projectile is a parabola irrespective of its velocity of projection. Statement-II : Trajectory of a projectile is a parabola when variation of g, (acceleration due to gravity) can be neglected.

When angle of projection is …... Range of projectile will be maximum.

The equation of a projectile is y=sqrt(3)x-(gx^(2))/(2) the angle of projection is:-

A ball is projected from ground in such a way that after 10 seconds of projection it lands on ground 500 m away from the point of projection. Find out :- (i) angle of projection (ii) velocity of projection (iii) Velocity of ball after 5 seconds

A ball is projected horizontally. After 3s from projection its velocity becomes 1.25 times of the velocity of projection. Its velocity of projection is