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If potential energy due to attractive fo...

If potential energy due to attractive force in circular path of radius r is `U=-k/(2r^2)`, then its total energy = …... .

Text Solution

Verified by Experts

The correct Answer is:
zero
`U=-k/(2r^2)rArr(dU)/(dr)=+k/r^3`
`:.F=k/r^3`
But for circular motion, centipetal force
`F=(mv^2)/r`
`:.(mv^2)/r=k/r^3`
`:. 1/2mv^2=k/(2r^2)`
`:. K=k/(2r^2)`
`:.` Total energy `E=U+K=-k/(2r^2)+k/(2r^2)=0`
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