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Time period of mars to revolve around Su...

Time period of mars to revolve around Sun is 8 times greater than that of Mercury. If distance of Mercury from Sun is `5.79xx10^10` m then that of Mars is approximately …... .

Text Solution

Verified by Experts

The correct Answer is:
`23.16xx10^10m`
Time period `T propr^(3/2)`
`:.T_"Mars"/T_"Mercury"=(r_"Mars"/r_"Mercury")^(3/2)`
`:.(8)^(2/3)=r_"Mars"/r_"Mercury"`
`:.4=r_"Mars"/(5.79xx10^10)`
`:.r_"Mars"=4xx5.79xx10^10`
`=23.16xx10^10m`
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