How much positive and negative charge is there in a cup of water ?

Explanation

Mass of water in a cup can be taken approximately 250 g (which actually should have
been given in the statement).
In one molecule of water, there are 2 hydrogen
atoms and 1 oxygen atom. Hence, in one molecule of water there are 2 + 8 = 10 protons and 2 + 8 = 10 electrons. Let it be x.
If there are N no. of water molecules in a given mass then magnitude of its positive charge (or negative charge) would be, Q = Nxe ... (1)
If no. of moles of water molecules is \i then we
have,
`mu = M/M_(0) = N/N_(A) rArr N = (MN_(A))/M_(0)`.......(2)
where M = given mass of water = 250g
`M_(0)` = molar mass of `H_(2)O` molecules
(`2 xx` molar mass of H-atoms) + (molar mass of O-atom) = 2(1) + 16 = 18 g/mol
N= total no. of water molecules
`N_(A)`= Avogadro number
From equation (1) and (2)
`Q = (MN_(A))/M_(0).xe`
`therefore Q =(250 xx 6.02 xx 10^(23) xx 10 xx 1.6 xx 10^(-19))/18`
`therefore Q = 1.338 xx 10^(7)` C