Suppose that the particle in Exercise in 1.33 is an electron projected with velocity `v_x = 2.0 xx 10^6 ms^(-1)` . If E between the plates separated by 0.5 cm is `9.1 xx 10^2` N/C, where will the electron strike the upper plate ?
`(|e| = 1.6 xx 10^(-19) C, m_(e) = 9.1 xx 10^(-31) kg)`

Explanation

Here, electron strikes upper plate and so upper plate must be positive.

Now from equation (5) of above example no. 33 we have,
`y=(qEx^(2))/(2mv_(s)^(2))`
`therefore x^(2) = (2ymv_(x)^(2))/(qE)`
`therefore x=((2ymv_(x)^(2))/(qE))^(1//2)`
`therefore x = 1.125 xx 10^(-2)` m