80 microC charge is given on sphere of 4 cm radius and `40 muC` charge is given on sphere of 6 cm radius. If they are connected by a conducting wire, then charge transferred from sphere of 4 cm radius to sphere of 6 cm radius will be......

Options

A. `48 muC`
B. `72 muC`
C. `32 muC`
D. `36 muC`

Answer

C

Explanation

If sphere of radii 4 cm and 6 cm are called 1 and 2 respectively, then total charge,
`Q = Q_(1) + Q_(2)`
=40 + 80
= `120 muC`
Charge on both sphere after connecting by wire,
`Q_(1) = 48 muC` and `Q_(2) = 72 muC` by using formula `Q(r_(2)/(r_(1) +r_(2)))`
`therefore (80 muC - 48muC) = 32 muC` will be transferred from sphere of 4 cm to sphere of 6 cm radius.