S.I. unit of permittivity (e0) ......

Options

A. `C^(2)N^(-1)M^(-2)`
B. `N^(1)M^(2)C^(-1)`
C. `N^(1)M^(2)C^(-2)`
D. `A^(1)M^(-1)C^(0)`

Answer

A

Explanation

`F =(q_(1)q_(2))/(4piE_(0)r^(2))`
`therefore E_(0) = (q_(1)q_(2))/(4piFr^(2))`
`therefore` Unit of `E_(0) = ("Coulomb")^(2)/(Nm^(2)) = C^(2)N^(-1)m^(-2)`