If two opposite electric charges having same magnitude are 10 cm away from each other, they experience 0.9N attractive force then magnitude of electric charges will be......

Options

A. `1pC`
B. 1 nC
C. `1 muC`
D. 1 mC

Answer

C

Explanation

Here, `F = (kq^(2))/r^(2)`
`F = 0.9 N, k = 9 xx 10^(9) SI, gamma = 10 cm = 10^(-2) cm`
`therefore q^(2) = (Fr^(2))/k = (0.9 xx 10^(-2))/(9 xx 10^(9)) = 10^(-12)`
`therefore q = 1 xx 10^(-6) C, therefore q = 1muC`