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An electron falls freely in electric fie...

An electron falls freely in electric field of `9.1 xx 10^3 NC^(-1)`, then acceleration of electron is .......

A

`1.6 xx 10^(13) ms^(-2)`

B

`1.6 xx 10^(15) cm//s^(2)`

C

`1.6 xx 10^(15) ms^(-2)`

D

`1.6 xx 10^(11) ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`a = (Ee)/m = (9.1 xx 10^(3) xx 1.6 xx 10^(-19))/(9.1 xx 10^(-31))`
`=1.6 xx 10^(15) m//s^(2)`
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