When an electron and a proton are both placed in an electric field ........

Options

A. (A) the electric forces acting on them are equal in magnitude as well as direction.
B. (B) only magnitudes of forces are same.
C. (C) accelerations produced in them are same.
D. (D) magnitudes of accelerations produced in them are same.

Answer

B

Explanation

Since acceleration of electron `a_(e) = (Ee)/m_(e)` and acceleration of proton `a_(p) = (Ee)/m_(p)`
But `m_(e) ne m_(0), therefore a_(e) ne a_(p)`
So, options (C) and (D) are wrong. And `vecF_(e) =-evecE` and `vecF_(p) = +evecE`
`therefore` Direction is opposite for electric forces. `therefore |vecF_(e)| =|vecF_(p)|` so, only magnitudes of forces are same.