The electric dipole moment of an HCl atom is `3.4 xx 10^(-30)` Cm. The charges on both atoms are unlike and of same magnitude. Magnitude of this charge is ........The distance between the charges is 1 A.

Options

A. `1.7 xx 10^(-20)` C
B. `3.4 xx 10^(-20)` C
C. `6.8 xx 10^(-20)` C
D. `3.4 xx 10^(-10)` C

Answer

B

Explanation

`p = 3.4 xx 10^(-30)` cm
`2a = 1.0A = 10^(-10)` m
q=?
p=(2a)q
`therefore q = p/(2a) = (3.4 xx 10^(-30))/10^(-10) = 3.4 xx 10^(-20)` C