the number of electric field lines leaving the positive 0.5 C charge placed in the medium of dielectric constant K = 10 are .......

Options

A. `5.65 xx 10^(9)`
B. `1.13 xx 10^(11)`
C. `9 xx 10^(9)`
D. `8.85 xx 10^(-12)`

Answer

A

Explanation

`rArr N=phi` and `phi = q/(Kepsilon_(0))`
`therefore phi = 0.5/(10 xx 8.85 xx 10^(-12))`
`=0.5649 xx 10^(10)`
`=5.65 xx 10^(9)`