When a `10muC` charge is enclosed by a closed surface, the flux passing through the surface is `phi`. Now another `-10muC` charge is placed inside the closed surface, then the flux passing through the surface is.........

Options

A. `2phi`
B. `phi`
C. `4phi`
D. Zero

Answer

D

Explanation

`q_(1) = 10muC, q_(2)=-10muC`
`therefore sumq = q_(1) + q_(2) =10-10=0`
`therefore` Flux `phi =(sumq)/epsilon_(0)`, in this equation `sumq=0`
`therefore phi=0`