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In a region, steady and uniform electric...

In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in the region. The path of the particle will be a.......

A

Circle

B

Helix

C

Ellipse

D

Straight line

Text Solution

Verified by Experts

The correct Answer is:
D
The charged particle experience a force `F_(e)` in this region and after some time it experiences force `vecF_(m)=q(vecv xx vecb)` with velocity `vecv`.

Here `vecv || vecB, therefore F_(m) =qvBsin0^(@), therefore vecF_(m) =0`
So if the charge is positive then it is mov opposite to electric field and if it is negative move in straight line in the direction of elect: field.
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Knowledge Check

  • A positively charged particle is released from rest in an unform electric field. The electric potential energy of the charge

    A
    remains a constant because the electric field is uniform.
    B
    increases because the charge moves along the electric field.
    C
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    D
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  • A charged particle is moving in a uniform magnetic field. Then ______ .

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    its momentum changes but kinetic energy does not change.
    B
    its momentum and kinetic energy both change.
    C
    neither the momentum nor kinetic energy changes.
    D
    kinetic energy changes but the momentum does not change.

  • In given region electric and magnetic field are prpendicular to each other.Electron moving in this region do not get deflected,charge on cathode will be….. [V=potential between anode and cathode]

    A
    `(B^(2))/(2VE^(2))`
    B
    `(2VB^(2))/(E^(2))`
    C
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