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Suppose [epsilon(0)] is permittivity of ...

Suppose [`epsilon_(0)`] is permittivity of free sapce. If M = mass, L = length, T = time and A = electric current, then.........

A

`|epsilon_(0)| = [M^(-1)L^(-3)T^(2)A]`

B

`|epsilon_(0)| = [M^(-1)L^(-3)T^(4)A^(2)]`

C

`|epsilon_(0)| = [M^(-1)L^(-3)T^(4)A^(2)]`

D

`|epsilon_(0)|= [M^(-1)L^(2)T^(-1)A^(-2)]`

Text Solution

Verified by Experts

The correct Answer is:
B
`F = (q_(1)q_(2))/(4piepsilon_(0)r^(2)) rArr epsilon_(0) = (q_(1)q_(2))/(4piFr^(2))`
`therefore |epsilon_(0)| =(|q_(1)||q_(2)|)/(4piFr^(2))` `[therefore 4pi "dimensionless"]`
`=((AT)(AT))/((M^(1)L^(1)T^(-2))(L^(2))) = M^(-1)L^(-3)T^(4)A^(2)`
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