A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = `10^(-12)` F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?

Explanation

Capacitance of capacitor with air as medium between the plates ,
`C_(0)=(in_(0)A)/(d)`
`8 xx10^(-12)= (in_(0)A)/(d)`
Now, dielectric fHled between two plates of capacitor and the distance between the plate is reduced to half, then the capacitance will be,
`C = (in_(0)A)/((d)/(2)) = (2K in_(0)A)/(d)`
`:. C= 2 xx6xx8xx10^(-12) ` ( From equation (1))
`=96 xx10^(-12) F `
`:. C = 96p E `