Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel
(a) What is the total capacitance of the combination?
(b) Determine the charge on each capacitor if the combination is connected to a 100 V supply

Explanation

For all parallel combination of the capacitors equivalent capacitance,
`C_(p) = C_(1) +C_(2)+C_(3)`
where `C_(1)=2` pF `C_(2)= 3 pF` and `C_(3) = 4 pF `
=2+3+4
=9 pF
`= 9xx10^(-12)` F
(b)
Suppose, the `q_(1),q_(2)` and `q_(3)` are the charges on capacitor `C_(1), C_(2)` and `C_(3)` respectively and supply voltage is 100 V.
`:. q_(1)=C_(1)V=2xx10^(-12) xx100=2xx10^(-10)C`
`q_(2)=C_(2)V= 3xx10^(-12)xx10^(-12)xx100=3xx10^(10)C `
`q_(3)= C_(3)V= 4xx10^(-12)xx100= 4xx10^(10)C`