An electrical technician requires a capacitance,of 2 `muF ` in a circuit across a potential difference of 1 kV. A large number of ` 1 muF` capacitors are available to him each of which can withstand a potential difference of more than 400 V. Suggest a possible arrangement that requires the minimum number of capacitors .

Explanation

For obtain 2 `mu`F capacitance and p.d. of 1 kV number of capacitor connected in series of `1mu` capacitor and such m series connected i parallel
For number of capacitor in each row is given a
`p.d. = (V)/(n) = (1000)/(n)`
`400 = (1000)/(n)`
`:. n = (1000)/(400) `
`:. n = 2.5`
but no. of capacitor should be in integer
`:. ` n =3
The equivalent of capacitance of composition connection ,
`(m)/(n) = 2 implies m=2n`
= `2xx3`
=6
Required number of capacitor = mn
`= 6xx3`
= 18
This composite connection is shown as figure