Equipotential surfaces,

Options

A. Are closer in regions of large elelctric fields compared to regions of lower electric fields
B. will be more crowded near sharp edges of a conductor.
C. will be more crowded near regions of large charge densities.
D. will always be equally spaced.

Answer

A, B, C

Explanation

The potential difference between any two points on equipotential surface is zero and their potential are equal.
Electric field and electric potential is related to,
`E=- (dV)/(dr)`
`:. E prop (1)/(dr)`
means the electric field intensity E is inversely proportional to the separation between two equipotential surfaces. So equipotential surfaces are closer in regions of large electric fields.
And the electric field is larger near the sharp edge due to larger charge density as A is very small surface charge density.
`:. sigma = (V)/(A)` and according to E `= (kq)/(r^(2))` as `sigma` increases q increases and E increase .
Hence, as the dimension of conductor increases electric potential and electric field decreases. Hence, near sharp edges of charged conductor both electric potential and electric field Increases and so equipotential surfaces are crowded.