Electric field on surfaces of two spheres of radius `r_(1)` and `r_(2)` are same, then ratio of their electric potential will be ....... .

Options

A. `(r_(1)^(2))/(r_(2))`
B. `(r_(2)^(2))/(r_(1)^(2))`
C. `(r_(1))/(r_(2))`
D. `(r_(2))/(r_(1))`

Answer

A, B

Explanation

`E_(1)=(kq)/(r_(1)^(2))=(kq)/(r_(1))xx(1)/(r_(1))=(V_(1))/(r_(1))`
`E_(2) =(kq)/(r_(2)^(2))=(kq)/(r_(2))xx(1)/(r_(2))=(V_(2))/(r_(2))`
but `E_(1)=E_(2):. (V_(1))/(r_(1))=(V_(2))/(r_(2)):. (V_(1))/(V_(2))=(r_(1))/(r_(2))`