A particle having mass 1 g and electric charge `10^(-8) C ` travels from a point A having electric potential 600 V to the point B having zero potential. What would be the change in its kinetic energy ?

Options

A. `-6 xx10^(-6) ` erg
B. `-6 xx10^(-6) `J
C. `6xx10^(-6) ` J
D. `6 xx10^(-6) ` erg

Answer

A

Explanation

From the definition of electric potential, work done by electric field in moving a unit positive charge from point A to B = W = 600 J
`:. ` Work done in moving `10^(-8)` C charge from point A to B `= 600xx10^(-8) =6xx10^(-6)J`
According to work energy theorem ,
`W = Delta :. W = Delta K = 6xx10^(-6)` J