For a point on the axis of the electric dipole `theta =` 0 and `theta = pi` = .. .. .. .. . , .........

Options

A. `-(kP)/(r^(2)),+(kP)/(r^(2))`
B. `+(kP)/(r^(2)),-(kP)/(r^(2))`
C. 0,0
D. `+(kP)/(r),-(kP)/(r)`

Answer

B

Explanation

For a point on dipole axis `theta = 0^(@)` and `theta = pi`
`:. V =pm = (kP)/(r^(2))`