For a capacitor the distane between two plates is 4x and the electric field between them is `E_(0)`. Now a dielectric slab having dielectric constant 3 and thickkness x is placed between them in contact with one plate. In this condition what is the p.d. between its two plates ?

Options

A. `(10 E_(0)x)/(3)`
B. `(11E_(0)x)/(3)`
C. `(13 E_(0)x)/(3)`
D. `(9E_(0)x)/(3)`

Answer

A, C

Explanation

`V = (E_(0))/(K) x+3 E_(0)x `
`= (E_(0))/(3) x+ 3E_(0)x = (E_(0)x+9E_(0)x)/(3) = (10E_(0)x)/(3)`