Energy of a charged capacitor is U. Now it is. removed from the battery and then it is connected to another uncharged capacitor having the capacitance twice the first one In parallel. The energy of first and second capacitors respectively is ......

Options

A. `(1)/(9) U, (1)/(9)` U
B. `(2)/(9) U, (1)/(9) U`
C. `(1)/(9) U, (2)/(9) U`
D. `(2)/(9) U, (2)/(9)` U

Answer

A, B

Explanation

By connecting two capacitors in parallel, charge on one capacitor is `(Q)/(3)` and on second capacitor is `(2Q)/(3)`.
`U (Q^(2))/(2C)`
`U_(1)=(((Q)/(3))^(2))/(2C)=(Q^(2))/(9xx2C)=(U)/(9)`
`U_(2)=(((2Q)/(3))^(2))/(2xx2C)=(4Q^(2))/(9xx2xx2C) = (2U)/(9)`