Home
Class 12
PHYSICS
Tell the proper reason for the earth's m...

Tell the proper reason for the earth's magnetic field to occur.

Promotional Banner

Topper's Solved these Questions

  • MAGNETISM AND MATTER

    KUMAR PRAKASHAN|Exercise SECTION B Numericals (Numerical From Textual Illustrations)|18 Videos
  • MAGNETISM AND MATTER

    KUMAR PRAKASHAN|Exercise SECTION B Numericals (Numerical From Textual Exercise)|25 Videos
  • MAGNETISM AND MATTER

    KUMAR PRAKASHAN|Exercise SECTION A QUESTIONS - ANSWERS (5.7 Permanent Magnets And Electromagnets)|3 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    KUMAR PRAKASHAN|Exercise Section D ( MCQs asked in Cometitive Exams )|39 Videos
  • MOVING CHARGES AND MAGNETISM

    KUMAR PRAKASHAN|Exercise SECTION D (MCQs ASKED IN COMPETITIVE EXAMS)|34 Videos

Similar Questions

Explore conceptually related problems

Name the elements of the earth's magnetic field.

At a certain place, the vertical component of the earth's magnetic field is 0.4 xx 10^(-4) T and horizontal component is 0.3 xx 10^(-4) T. What will be the total intensity of magnetic field of the earth ?

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26G and the dip angle is 60^(@) . What is the magnetic field of the earth at this location?

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.1414 G and the dip angle is 45°. What is the magnetic field of the earth at this location ?

A long straight horizontal cable carries a current of 2.5 A in the direction 10^@ south of west to 10^@ north of east. The magnetie meridian of the place happens to be 10^@ west of the geographie meridian. The earth's magnetic field at the location is 0.33 G, and the angle of dip is zero. Locate the line of neutral points (ignore the thickness of the cable)? (At neutral potnts, magnetic field due to a current-carying cable is equal and opposite to the horizontal component of earth's magnetic field.)

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north up pointing down at 22^@ with the horizontal. The horizontal component of the earth's magnetic field at the place is known to be 0.35 G. Determine the magnitude of the earth's magnetic field at the place.

The lines of force due to earth's magnetic field are ....... .

A circular coil of radius 10 cm, 500 turns and resistance 2Omega is placed with its plane perpendicular to the horizontal component of the earth's magnetic field. It is rotated about its vertical diameter through 180^@ in 0.25 s. Estimate the magnitudes of the emf and current induced in the coil. Horizontal component of the earth's magnetic field at the place is 3.0xx10^(-5) T.