In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26G and the dip angle is `60^(@)`. What is the magnetic field of the earth at this location?

Explanation

From above figure,
`cos I = (B_h)/( B)`
`therefore B= (B_h)/( cosI)`
`therefore B= (0.26) /( cos 60^(@) )`
`therefore B= (0.26) /( cos 60^@)`
`therefore B= (0.26)/( (1)/(2) )`
`therefore B= 0.52 G` (Gauss)