Home
Class 12
PHYSICS
From molecular view point, discuss the t...

From molecular view point, discuss the temperature dependence of susceptibility for diamagnetism, paramagnetism and ferromagnetism.

Text Solution

Verified by Experts

Susceptibility of magnetic materials `chi = (M)/( H)`,
where M = magnetisation intensity.
H = magnetising force
Diamagnetism is due to the orbital motion of electrons in an atom developing magnetic moment opposite to applied field. Thus, resultant magnetic moment is zero and hence the susceptibility of diamagnetic material is not much affected by temperature.
Para and ferromagnetism is due to alignments of atomic magnetic moments in the direction of the applied field. As the temperature raised, the alignment is disturbed, resulting decrease in susceptibility of both with increase in temperature.
Promotional Banner

Topper's Solved these Questions

  • MAGNETISM AND MATTER

    KUMAR PRAKASHAN|Exercise SECTION C NCERT Exemplar Solution ( Short Answer Type Questions )|5 Videos

  • MAGNETISM AND MATTER

    KUMAR PRAKASHAN|Exercise SECTION C NCERT Exemplar Solution (Long Answer Type Questions )|5 Videos

  • MAGNETISM AND MATTER

    KUMAR PRAKASHAN|Exercise SECTION C NCERT Exemplar Solution (Multiple Choice Questions (More than One Options) )|5 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    KUMAR PRAKASHAN|Exercise Section D ( MCQs asked in Cometitive Exams )|39 Videos

  • MOVING CHARGES AND MAGNETISM

    KUMAR PRAKASHAN|Exercise SECTION D (MCQs ASKED IN COMPETITIVE EXAMS)|34 Videos

Similar Questions

Explore conceptually related problems

Each phase of a material can exits only in certain regions of pressure and temperature . P-T phase diagrams, in which pressure is plotted versus temperature, show the regions corresponding to various phases and phase transformations . P-V diagrams, on the other hand , can be used to study pressure volume relationship at a constant temperature. If the liquid and gaseous phases of a pure substances are heated together in a closed container, both the temperature and the vapor pressure will increase until a point is reached at which the two phases can no longer be distinguished from one another. The temperature and pressure at which this occurs are called the critical temperature and pressure. Exceeding either of these parameters, by itself ,will cause the "gas"//"liguid" phase transition to disappear. if the other variable is then changed as well, while the first variable is maintained above its critical point , a gradual transition will occur between the gaseous and liquid phases, with no clear boundary.(The liquid and solid phases, on the other hand , maintain a distinct boundary at all pressure above the triple point). Shown in figure is a combined P-T phase diagram for material A and B . If heat is added to solids A and B , each in a container that is open to the atmosphere :-

Each phase of a material can exits only in certain regions of pressure and temperature . P-T phase diagrams, in which pressure is plotted versus temperature, show the regions corresponding to various phases and phase transformations . P-V diagrams, on the other hand , can be used to study pressure volume relationship at a constant temperature. If the liquid and gaseous phases of a pure substances are heated together in a closed container, both the temperature and the vapor pressure will increase until a point is reached at which the two phases can no longer be distinguished from one another. The temperature and pressure at which this occurs are called the critical temperature and pressure. Exceeding either of these parameters, by itself ,will cause the "gas"//"liguid" phase transition to disappear. if the other variable is then changed as well, while the first variable is maintained above its critical point , a gradual transition will occur between the gaseous and liquid phases, with no clear boundary.(The liquid and solid phases, on the other hand , maintain a distinct boundary at all pressure above the triple point). Shown in figure is a combined P-T phase diagram for material A and B . Which is true about the substance in figure?

Why are the small numbers of cause of worry from the surviving tigers a point of view of genetics ?

Surafce tension is exhibited by liquids due to force of attraction between the molecules of the liquid .The surface tension decreases with increases in temperature and vanishes at boiling point Given that the latent heat of vaporization for water L_(v)=540(kcal)/(kg) the mechanical equivalent of heat J=4.2(J)/(cal) density of water rho_(w)=10^(3)kgl^(-1) ,Avogadro'sno. N_(A)=6.0xx10^(26)k " mole"^(-1) . Molecular weight of water M_(A)=10kg , for 1k mole . (a) Estimate the energy required for one molecule of water to evaporated. (b) Show that the inter molecular distance for water is d=((M_(A))/(N_(A))xx(1)/(rho_(w)))^((1)/(3)) and find its value. (c ) 1 g of water in the vapour state at 1 atm occupies 1601cm^(3) , estimate the intermolecular distance at boiling point in the vapour state. (d) During vaporisation a molecule overcomes a force F, assumed constant to go from an inter molecular distance d to d .Estimate the value of F. (e ) Caculate (F)/(d) , which is a measure of the surface tension.

Discuss the pattern of interference fringes obtained on the screen away from the two point sources.

Consider the MB shown in the diagram, let the resistance X have temperature coefficient alpha_(1) and the resistance from the RB have the temperature coefficient alpha_(2) . Let the reading of the meter scale be 10 cm from the LHS. if the temperature of the two resistance increase by small temperature DeltaT then what is the shift in the position of the null point ? Neglect all the other changes in the bridge due to temperature rise.

A sample of 2 kg monoatomic helium (assumed ideal ) is taken from A to C through the process ABC and another sample of 2 kg of the same gas is taken through the process ADC (seefig). Given molecular mass of helium = 4 . What is the temperature of helium in each of the states A ,B , C and D ?