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Force acting on a magnetic pole of 7xx 1...

Force acting on a magnetic pole of `7xx 10^(-2)` Am is `31.5`N. Magnetic field at that point is …

A

`4 xx 10^(-2) T`

B

`4.5 xx 10^(-2) T`

C

`3.5 xx 10^(2) T`

D

`3 xx 10^(2) T`

Text Solution

Verified by Experts

The correct Answer is:
B
Force acting on a magnetic pole due to magnetic field `overset(to)(F) = p overset(to)(B)`
Pole strength `p=7 xx 10^(-2) "Am", F= 31.5 N`
`therefore overset(to)(B) = (overset(to)(F))/( p) = (3.15)/(7 xx 10^(2) ) = 4.5 xx 10^(-2) `T
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